Light from a source travel out with a velocity c. If the source moves away from the observer with a velocity v, then relative velocity of light w.r.t observer is

c

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c + v

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c - v

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\sqrt{c^{2} + v^{2}}

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Solution

The correct option is A $c$
Consider two particles with velocity u and w. The expression for the relative velocity can be given by
$v = \frac{w - u}{1 - \frac{w u}{c^{2}}}$

If one of the particles is light, $w = c$ .
This gives relative velocity of light $v = c$ .

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Light from a source travel out with a velocity c. If the source moves away from the observer with a velocity v, then relative velocity of light w.r.t observer is

The correct option is A cConsider two particles with velocity u and w. The expression for the relative velocity can be given byv=w−u1−wuc2If one of the particles is light, w=c.This gives relative velocity of light v=c.

The correct option is A $c$
Consider two particles with velocity u and w. The expression for the relative velocity can be given by
$v = \frac{w - u}{1 - \frac{w u}{c^{2}}}$

If one of the particles is light, $w = c$ .
This gives relative velocity of light $v = c$ .