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Formation of Complexes

Light green s...

Question

Light green solution of (A) does not give blue coloured ppt with $K_{4} [{F e (C N)}_{6}]$ but on adding a drop of ${H N O}_{3}$ , blue ppt. of (B) appears. However, (A) gives blue colour (C) with $K_{3} [{F e (C N)}_{6}]$ . Identify (A) if it, also gives white ppt with $A g {N O}_{3}$ solution?

{F e C l}_{2}

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{F e I}_{2}

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{F e B r}_{2}

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None of the above

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Solution

The correct option is A ${F e C l}_{2}$
The light green solution of (A) is due to presence of $F e C l_{2}$ .
It reacts with $K_{4} [{F e (C N)}_{6}]$ to form white precipitate.

$2 F e C l_{2} + K_{4} [{F e (C N)}_{6}] \to F e_{2} [F e (C N)_{6}] white precipitate + 4 K C l$

$H N O_{3}$ oxidizes ${F e}_{2} [{F e (C N)}_{6}]$ to ${F e}_{4} {[{F e (C N)}_{6}]}_{3}$ .

The colour of the precipitate changes from white to blue.

$F e C l_{2}$ reacts with $A g N O_{3}$ to form white precipitate of $A g C l$ .

$F e C l_{2} + 2 A g N O_{3} \to F e (N O_{3})_{2} + A g C l white precipitate$

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