Light is incident normally on a completely absorbing surface with an energy flux of 25Wcm−2. if the surface has an area of 25cm−2, the momentum transferred to the surface in 40 min time duration will be :
A
5.0×10−3Ns
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B
3.5×10−6Ns
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C
1.4×10−6Ns
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D
6.3×10−4Ns
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Solution
The correct option is D5.0×10−3Ns Pressure = IC Force = Pressure × Area = IC. Area Momentum transferred = Force . Δt =IC. Area .Δt =25×1043×108×25×10−4×40×60 →5×10−3N−s