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Question

Light is incident on a glass surface at polarizing angle of 57.5. Then the angle between the incident ray and the refracted ray is:

A
57
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B
115
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C
205
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D
145
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Solution

The correct option is D 57

Given that,

Polarizing angle for glass = 57.50

Angle of refraction = r

Now, refractive index of the glass

μ=tanθp

1.4=tan(57.50)

Now, from Snell’s law

μ1sini=μ2sinr

1×sin(57.50)=1.4×sinr

sinr=0.814191.4

sinr=0.5816

r=sin1(0.5816)

r=0.6207

Now, angle of deviation

δ=ir

δ=57.50.6207

δ=56.87

δ=570

Hence, the angle between the incident ray and the refracted ray is 570


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