Question

Light of 630 nm produces fringes of fringe width 8.31 nm. A second wavelength gives fringes of fringe width 7.61 nm. What is its wavelength?

• A. 451 nm
• B. 523 nm
• C. 577 nm
• D. 653 nm

Answer 1

The correct option is C 577 nm

$\frac{{\beta }_1}{{\beta }_2}=\frac{{\lambda }_1}{{\lambda }_2}$