Light of frequency v falls on material of threshold frequency $v_{0}$ . Maximum kinetic energy of emitted electron is proportional to:

v - v_{0}

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\sqrt{v - v_{0}}

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v_{0}

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Solution

The correct option is A $v - v_{0}$

Apply einstein equation of photoelectric effect.
$W = W_{0} + K E_{m a x}$
$h v = h v_{0} + K E_{m a x}$
$K E_{m a x} = h (v - v_{0})$
$K E_{m a x \propto} (v - v_{0})$

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