Light of the wavelength 550nm falls normally on a slit of width 22.0×10−5cm. The angular position of the second minima from the central maxima will be :
A
π8
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B
π12
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C
π6
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D
π4
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Solution
The correct option is Bπ12 From given, sinθdan=mλd=2×550×10−922×10−7
On solvig we get θ=30∘.