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Question

Light of wavelength 0.6μm from a sodium lamp falls on a photocell and causes the emission of photoelectrons for which the stopping potential is 0.5 V. With light of wavelength 0.4μm from a mercury vapor lamp, the stopping potential is 1.5 V. Then, the work function [in electron volts] of the photocell surface is

A
0.75 eV
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B
1.5 eV
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C
3 eV
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D
2.5 eV
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Solution

The correct option is A 1.5 eV
Energy of 0.6μm is hc0.6106 =2.05eV

stopping potential is 0.5v i.e, K.E=0.5eV
work function of material = 2.050.5eV
= 1.5eV

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