Light of wavelength $300 \times 10^{- 9} m$ strikes a metal a metal surface with photoelectric work function of $2.13 e V$ . The kinetic energy of photoelectron is

3.216 X 10^-19ergs

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3.217 X 10^-19 J

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32.16 X 10^-19 ergs

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32.16 X 10^-19 J

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Solution

The correct option is B
3.217 X 10^-19 J

$E = \frac{h c}{λ}$ $E_{0}$ = $2.13 e v$

= $\frac{6.625 \times 10^{- 34} \times 10^{8}}{3 \times 10^{- 7}} = 6.625 \times 10^{- 19} J$

$E_{0} = 2.13 \times 1.6 \times 10^{- 19} = 3.408 \times 10^{- 19} J$

$K . E . = E - E_{0}$

= $6.625 \times 10^{- 19} - 3.408 \times 10^{- 19}$

= $3.217 \times 10^{- 19} J$

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Similar questions

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Light of wavelength 300 × 10−9m strikes a metal a metal surface with photoelectric work function of 2.13 eV. The kinetic energy of photoelectron is

The correct option is B 3.217 X 10-19 J E = hcλ E0 = 2.13ev = 6.625 × 10−34 × 1083 × 10−7 = 6.625 × 10−19 J E0 = 2.13 × 1.6 × 10−19 = 3.408 × 10−19 J K.E. = E − E0 = 6.625 × 10−19 − 3.408 × 10−19 = 3.217 × 10−19 J

Light of wavelength $300 \times 10^{- 9} m$ strikes a metal a metal surface with photoelectric work function of $2.13 e V$ . The kinetic energy of photoelectron is