Light of wavelength 400 angstorm is incident on a surface for which the threshold wavelength photoelectrons is 5420 angstrom. The work function of sodium is ?

4.58 eV

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2.29 eV

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1.14 eV

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0.57 eV

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Solution

The correct option is A 2.29 eV
As we know that
$ϕ = \frac{12345}{λ_{0}}$

$ϕ = \frac{12345}{5420} = 2.29 e V$

Hence, option "B" is correct.

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Light of wavelength 400 angstorm is incident on a surface for which the threshold wavelength photoelectrons is 5420 angstrom. The work function of sodium is ?

The correct option is A 2.29 eVAs we know thatϕ=12345λ0ϕ=123455420=2.29 eVHence, option "B" is correct.

The correct option is A 2.29 eV
As we know that
$ϕ = \frac{12345}{λ_{0}}$

$ϕ = \frac{12345}{5420} = 2.29 e V$

Hence, option "B" is correct.