Light of wavelength 4000 Angstrom falls on the surface of cesium. Calculate the energy of the photoelectron emitted. The critical wavelength for photoelectric effect in cesium is 6600 Angstrom.

Open in App

Solution

Suggest Corrections

Similar questions

The light of wavelength 4000 angstrom falls on a metal whose critical wavelength of photoelectric effect is 6600 angstrom .Calculate the kinetic energy .

Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350 nm is incident on a cesium surface. Work function of cesium = 1.9 eV.

Q. Photoelectrons are liberated by ultraviolet light of wavelength

3000 ˚ A

from a metallic surface for which the photoelectric threshold is

4000 ˚ A

. Calculate de Broglie wavelength of electrons emitted with maximum kinetic energy.

Q. Light of wavelength 5000

A^{o}

falls on a sensitive plate with photoelectric work function 1.9eV. The maximum kinetic energy of the photoelectrons emitted will be

Q. Threshold wavelength of tungsten is 2300 angstrom. If ultraviolet light of wavelength 1800 angstrom is incident on it, then the maximum kinetic energy of photoelectrons would be ?

Join BYJU'S Learning Program