Light of wavelength $5000^{o} A$ falls on a sensitive plate with photo electric work function $1.9 e V .$ The kinetic energy of the photo electrons emitted will be:

0.58 e V .

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2.48 e V .

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1.24 e V .

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1.16 e V .

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Solution

The correct option is A $0.58 e V .$
From photoelectric equation
$K E = \frac{h c}{λ} - W \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{5000 \times 10^{- 10}} - 1.9 \times 1.6 \times 10^{- 19} = 0.58 e V$

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Light of wavelength 5000oA falls on a sensitive plate with photo electric work function 1.9eV. The kinetic energy of the photo electrons emitted will be:

The correct option is A 0.58eV.From photoelectric equationKE=hcλ−W6.6×10−34×3×1085000×10−10−1.9×1.6×10−19=0.58eV

Light of wavelength $5000^{o} A$ falls on a sensitive plate with photo electric work function $1.9 e V .$ The kinetic energy of the photo electrons emitted will be:

The correct option is A $0.58 e V .$
From photoelectric equation
$K E = \frac{h c}{λ} - W \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{5000 \times 10^{- 10}} - 1.9 \times 1.6 \times 10^{- 19} = 0.58 e V$