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Question

Light of wavelength 6.5×107 meters is made incident on two slits, 1mm apart. The distance between third dark fringes and fifth bright fringe on a screen distant 1m from the slits will be:

A
0.35mm
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B
0.65mm
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C
1.63mm
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D
3.25mm
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Solution

The correct option is A 1.63mm

Distance of 3rd dark fringe from centre:
x3=(2n1)λD2d=(2×31)λD2d=5λD2d
Distance of 5th bright fringe from centre:
x5=nλDd=5λDd
x5x3=5λDd5λD2d=5λD2d=5×6.5×107×12×(1×103),
which gives distance = 1.63 mm


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