Light of wavelength 6000 Armstrong in air enters a medium of refractive index of 1.5 . What are the wavelength and frequency of light in that medium?
Can you please tell me that why I should take
v=3*10(raised to 8)/6000 Armstrong
Instead I can take v=3*10(raised to 8)/4000 Armstrong , because wavelength of light in that medium is 4000 Armstrong.
Light of wavelength 6000 Armstrong in air enters a medium of refractive index of 1.5 . What are the wavelength and frequency of light in that medium?
Can you please tell me that why I should take
v=3*10(raised to 8)/6000 Armstrong
Instead I can take v=3*10(raised to 8)/4000 Armstrong , because wavelength of light in that medium is 4000 Armstrong.
c = Speed of light in air → 3 X 10^8 m/s
W → Wavelength
n → Refractive index of the medium = 1.5
W in air = 6000 A = 6 X 10^-7 metres
λ → Frequency in air = c / W in air
= 5 X 10^14 Hz
n = W in air / W in the medium
1.5 = 6000 / W in the medium
W in the medium = 4000 A
Magnitude of frequency depends upon the light producing source hence it remains constant throughout ( 5 X 10^14 Hz) .
The frequency of light does not change on refraction. So frequency of light in the medium= 5×10^14 Hz.
To keep the frequency unchanged, the wavelength of light in the medium also decreases by the same factor as the decrease in the velocity of light. So altered wavelength of light in the medium= 6000A°/1.5 = 4000A° .
So frequency of light in the medium= 5×10^14 Hz.
Wavelength of light in the medium= 4000A°
c = Speed of light in air → 3 X 10^8 m/s
W → Wavelength
n → Refractive index of the medium = 1.5
W in air = 6000 A = 6 X 10^-7 metres
λ → Frequency in air = c / W in air
= 5 X 10^14 Hz
n = W in air / W in the medium
1.5 = 6000 / W in the medium
W in the medium = 4000 A
Magnitude of frequency depends upon the light producing source hence it remains constant throughout ( 5 X 10^14 Hz) .
The frequency of light does not change on refraction. So frequency of light in the medium= 5×10^14 Hz.
To keep the frequency unchanged, the wavelength of light in the medium also decreases by the same factor as the decrease in the velocity of light. So altered wavelength of light in the medium= 6000A°/1.5 = 4000A° .
So frequency of light in the medium= 5×10^14 Hz.
Wavelength of light in the medium= 4000A°
