Question

Light of wavelength $6000\stackrel{\circ }{A}$ is incident normally on a single slit of width $24\times {10}^{-5}cm$. Find out the angular position of second minimum from central maxima?

• A. ${15}^{\circ }$
• B. ${30}^{\circ }$
• C. ${45}^{\circ }$
• D. ${60}^{\circ }$

Answer 1

The correct option is B

${30}^{\circ }$

$sin\theta =\frac{2\lambda }{a}=\frac{2\times 6\times {10}^{-7}}{24\times {10}^{-5}\times {10}^{-2}}$

$\theta ={30}^{\circ }$