Light of wavelength 6328 ˙A is incident on a slit having a width of 0.2 mm. The width of the central maximum, measured from minimum to minimum of the diffraction pattern on a screen 9.0 metre away will be about:
A
0.36 degrees
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B
0.18 degrees
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C
0.72 degrees
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D
0.09 degrees
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Solution
The correct option is A 0.36 degrees Angular width of central max = θ=2λe=2×6328×10−100.2×10−3,θ=0.36∘