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Question

Light of wavelength 6328 ˙A is incident on a slit having a width of 0.2 mm.  The width of the central maximum, measured from minimum to minimum of the diffraction pattern on a screen 9.0 metre away will be about:
  1. 0.36 degrees
  2. 0.72 degrees
  3. 0.09 degrees
  4. 0.18 degrees


Solution

The correct option is A 0.36 degrees
Angular width of central max = θ=2λe=2×6328×10100.2×103,θ=0.36
 

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