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Question

Light of wavelength λ is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is--

A
d2λ
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B
2d2λ
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C
2dλ
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D
d22λ
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Solution

The correct option is D d22λ
Th position of first minimum above the central maxima,
y=λDd. . . . . . . ..(1)
So, the linear width of the central maxima will be
2y=2λDd
According to question,
2λDd=d
D=d22λ
The correct option is D.

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