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Question

Light of wavelength λ strikes a photo-sensitive surface and electrons are ejected with kinetic energy E. If the kinetic energy is to be increased to 2E, the wavelength must be changed to λ where


A

λ=λ2

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B

λ=2λ

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C

λ2<λ<λ

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D

λ>λ

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Solution

The correct option is C

λ2<λ<λ


E=hcλW0 and 2E=hcλW0
λλ=E+W02E+W0λ=λ(1+W0E2+W0E)
Since (1+W0E)(2+W0E)>12 so λ>λ2


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