Question

Light wavelength $550nm$ falls normally on a slit of width $22.0\times {10}^{-5}cm$. The angular position of the second minima from the central maximum will be (in radians)

• A. $\frac{\pi }{8}$
• B. $\frac{\pi }{12}$
• C. $\frac{\pi }{4}$
• D. $\frac{\pi }{6}$

Answer 1

The correct option is D $\frac{\pi }{6}$

for single slit, the angular position is given as

$sin\theta =\frac{n\lambda }{d}$

Here, n = 2

$sin\theta =\frac{2\times 550\times {10}^{-9}}{22\times {10}^{-7}}$

$sin\theta =\frac{1}{2}$

$\theta =\frac{\pi }{6}$