Light waves producing interference have their amplitudes in the ratio 3:2. The intensity ratio maximum and minimum of interference fringes is :
A
36:1
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B
9:4
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C
25:1
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D
6:4
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Solution
The correct option is C 25:1 Amplitudes ratio is 3/2 Let amplitudes by 3x and 2x At maxima amplitudes add up giving 5x At minima amplitudes substract giving −x Intensity ratio =251 because Intensity is square of amplitude.