LiH+B2H6Ether−−−→A. A is as follows
Diborane when treated with lithium hydride forms Lithium borhydride.
LiH+B2H6Ether−−−→LiBH4
BF3+LiH→A+LiBF4. A is as follows
B2H6.2NH3Δ−−−→200∘CA+H2. A is as follows
In the reaction
AlH3and LiH acts as
Look at the following reaction: LiH+AlH3⟶LiAlH4 Here AlH3 and LiH act as: