limh→0√x+h−√xh,x≠0
Rationalising the numerator
=limh→0(√x+h−√x)h×(√x+h+√x)(√x+h+√x)
=limh→0(x+h−x)(√x+h+√x)h
=1√x+√x
=12√x
Find the value of limh→ 0[2−h]+limh→ 0[2+h]