limx→0sin3xsin5x is equal to
35
We have, limx→0sin3xsin5x
At x=0, the value of the expression is in determinate form of 00
Applying L'Hospital Rule
Takin derivative of Numerator and Denominator,
limx→0ddxsin3xddxsin5x
⇒limx→0cos3xddx3xcos5xddx5x
limx→03cos3x5cos5x
Putting x=0, we get
The value of limit =3cos05cos0=35