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Question

limx0sin3xsin5x is equal to


A

3

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B

5

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C

35

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D

53

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Solution

The correct option is C

35


We have, limx0sin3xsin5x

At x=0, the value of the expression is in determinate form of 00
Applying L'Hospital Rule
Takin derivative of Numerator and Denominator,
limx0ddxsin3xddxsin5x
limx0cos3xddx3xcos5xddx5x
limx03cos3x5cos5x

Putting x=0, we get
The value of limit =3cos05cos0=35


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