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Byju's Answer
Standard XI
Mathematics
L'Hospital Rule to Remove Indeterminate Form
lim x → 0sin ...
Question
lim
x
→
0
s
i
n
3
x
s
i
n
5
x
=
A
-2
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B
3
5
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C
5
3
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D
15
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Solution
The correct option is
B
3
5
We have,
lim
x
→
0
s
i
n
3
x
s
i
n
5
x
This is an indeterminate limit of the form
0
0
Applying L'Hospital's Rule,
lim
x
→
0
s
i
n
3
x
s
i
n
5
x
=
lim
x
→
0
c
o
s
3
x
d
d
x
3
x
c
o
s
5
x
d
d
x
3
x
=
lim
x
→
0
3
c
o
s
3
x
5
c
o
s
5
x
Substituting x=0, the limit evaluates to
3
5
Suggest Corrections
0
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