limx→1logxx−1 is equal to
We have, limx→1logxx−1
At x=0, the value of the expression is the form 00
Applying L'Hospital Rule, we get
limx→1ddxlogxddx(x−1)
⇒limx→11x1=limx→11x
Since, (ddxlogx=1x)
Putting x=1, we get the value of the limit as 11=1