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Question

limx1f(x)=5, limx2g(x)=6 and limx1g(x)=2 find the value of limx1 ([g(x)]f(x)) ___

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Solution

limxaf(x) and limxag(x) exist,
limxa(f(x))g(x)=[limxaf(x)]limxag(x)
limx1([g(x)]f(x))=(limx1g(x))limx1f(x)
= 25
= 32


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