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Question

limx0sin2x21+cosx equals:

A
42
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B
4
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C
2
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D
22
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Solution

The correct option is A 42
limx0sin2x21+cosx=limx0sin2x22cos2x2=limx0sin2x2[1cosx2]=limx0sin2x22sin2x4=limx01622(sin2xx2)⎜ ⎜ ⎜ ⎜ ⎜(x4)2sin2x4⎟ ⎟ ⎟ ⎟ ⎟=1622=42

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