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Question

limx1π2sin1x1x is equal to :

A
2π
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B
π2
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C
12π
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D
π
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Solution

The correct option is A 2π
limx1π2sin1x1x

=limx1π2sin1x1x (π+2sin1x)

=12π limx1π2sin1x1x [00 form]

Applying L'Hospital Rule, we get
12π×limx121x2121x

=1π×limx121+x

=2π

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