Question

$\underset{x\to 2}{lim}\frac{x^2-5x+3}{x^2-1}=$

• A. $1$
• B. $-1$
• C. $2$
• D. none of these

Answer 1

Answer: (B)

$-1$

Now,

$\underset{x\to 2}{lim}\frac{x^2-5x+3}{x^2-1}$

$=\frac{2^2-5.2+3}{2^2-1}$

$=\frac{4-10+3}{3}$

$=\frac{-3}{3}$

$=-1$.