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Question

limnn!(n+1)!+n! is equal to


A

12

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B

0

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C

2

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D

1

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Solution

The correct option is B

0


limn[n!(n+1)!+n!]
=limn[n!(n+1)×n!+n!]
=limn[n!n!(n+1+1)]
=limn[1n+2]=0


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