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Question

limn[1n+1n+1+1n+2++12n]= [Karnataka CET 1999]


A
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B
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C

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D
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Solution

The correct option is D loge 2
limn[1n+1n+1+1n+2++12n]
=limn[1n+1n+1+1n+2++1n+n]
=1nlimn[1+11+1n+11+2n++11+nn]
=1nlimnnr=0[11+rn]=1011+xdx
=[loge (1+x)]10=loge 2loge 1=loge2

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