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Question

limπ 1n 2nr=1rn2+r2=

A
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B


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C


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D


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Solution

The correct option is A. 1+5

L=limπ2nr=1 1n. rn1+(rn)2=20 x1+x2dx

Put 1+x2=t2

xdx=t dt

x=0 then t=1

x=2 then t=5

Now,

20 x1+x2dx

=51 ttdt

=51 1 dt

=[t]51

=51

Hence, Option A is correct.


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