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Question

limπnk=1 kn2+k2 is equals to [Roorkee 1999]


A
12 log 2
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B
log 2
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C
π4
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D
π2
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Solution

The correct option is A 12 log 2
Let I=limπnk=1 kn2+k2=limπnk=1 1n(kn)1+(kn)2
I=10 x1+x2dx=12[log(1+x2)]10=12[log 2]

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