Limx - 0-z2-z-x2-8xz-4x2-8xz4 is equal to

lim _ x→ 0 x√( z ^ 2 ( z x ) #160; ^ 2 ) #160; /( √( 8xz 4 x ^ 2 ) +√( 8xz ) #160; ) #160; ^ 4 #160; =lim _ x→ 0 x√( 2zx x ^ 2 ) #16 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

L'Hospital Rule to Remove Indeterminate Form

limx → 0√z2-z...

Question

$l i m_{x \to 0} \frac{\sqrt[x^{3}]{z^{2} - (z - x)^{2}}}{(\sqrt[3]{8 x z - 4 x^{2}} + \sqrt[3]{8 x z})^{4}}$ is equal to

Open in App

Solution

Suggest Corrections

Similar questions

lim x \to 1 \frac{\sqrt[3]{7 + x^{3}} - \sqrt{3 + x^{2}}}{x - 1}

lim x \to 0 \frac{x \sqrt[3]{z^{2} - (z - x)^{2}}}{(\sqrt[3]{8 x z - 4 x^{2}} + \sqrt[3]{8 x z})^{4}}; (z \neq 0)

i .

lim x \to 1 [\frac{x^{2} + 1}{x + 100}]

i i .

lim x \to 2 [\frac{x^{3} - 4 x^{2} + 4 x}{x^{2} - 4}]

i i i .

lim x \to 2 [\frac{x^{2} - 4}{x^{3} - 4 x^{2} + 4 x}]

i v .

lim x \to 2 [\frac{x^{3} - 2 x^{2}}{x^{2} - 5 x + 6}]

v .

lim x \to 1 [\frac{x - 2}{x^{2} - x} - \frac{1}{x^{3} - 3 x^{2} + 2 x}]

2 x + 2 y - z)^{2}

If 2x - y + z = 0, then 4x² - y² + z² + 4xz is equal to

Join BYJU'S Learning Program