Question

${lim}_{x\to 0}\frac{1-cos2x}{x}$ is

• A. 0
• B. 1
• C. 2
• D. 4

Answer 1

The correct option is A

0

${lim}_{x\to 0}\frac{1-cos2x}{x}$
$={lim}_{x\to 0}\frac{2si{n}^{2}x}{x}$
$={lim}_{x\to 0}2x\times \frac{si{n}^{2}x}{x^2}$
$=0$