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Question

limx01+x1log(1+x)

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Solution

limx01+x1log(1+x)

=limx0(1+x1)(1+x+1)log(1+x)(1+x+1)

=limx0xlog(1+x)(1+x+1)

=limx01log(1+x)x×limx01(1+x+1)

=1×12=12


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