wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

limx1[[4x2x1]+3(x41)x31]=

Open in App
Solution

limx1(4x2x1+3(x41)x31)=4+3limx1(x1)(x3+x2+x+1)(x1)(x2+x+1)=4+3limx1x3+x2+x+1x2+x+1=4+3(4)(3)=0

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation and Rationalisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon