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Question

limx1[[4x2x1]+3(x41)x31]=

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Solution

limx1(4x2x1+3(x41)x31)=4+3limx1(x1)(x3+x2+x+1)(x1)(x2+x+1)=4+3limx1x3+x2+x+1x2+x+1=4+3(4)(3)=0

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