${lim}_{x \to 3} \frac{x^{2} - 9}{x + 2}$

Open in App

Solution

${lim}_{x \to 3} \frac{x^{2} - 9}{x + 2}$

$= \frac{3^{2} - 9}{3 + 2} = 0$

Suggest Corrections

Similar questions

lim x \to 3 \frac{x^{2} - 9}{\sqrt{2 x - 2 - \sqrt{x + 1}}}

{lim}_{x \to 3} \frac{x^{2} - 9}{x - 3}

Evaluate ${lim}_{x \to 3} \frac{x^{2} - 9}{x - 3}$

Evaluate (i) $l i m x \to 3 (\frac{x^{2} - 9}{x - 3})$

(ii) $l i m x \to 1 (\frac{(x^{2} - 4 x + 3)}{x - 1})$

{lim}_{x \to 3} (x^{2} - 9) [\frac{1}{x + 3} + \frac{1}{x - 3}]

Join BYJU'S Learning Program