Question

${lim}_{x\to -5}\frac{2x^2+9x-5}{x+5}$

Answer 1

$\underset{x\to -5}{lim}\frac{2x^2+9x-5}{x+5}\left(÷form\right)$

$=\underset{x\to -5}{lim}\frac{2x^2+10x-x-5}{x+5}$

$=\underset{x\to -5}{lim}\frac{2x\left(x+5\right)-1\left(x+5\right)}{x+5}$

$=\underset{x\to -5}{lim}\frac{\left(x+5\right)\left(2x-1\right)}{x+5}$

$=2\times \left(-5\right)-1$

$=-10-1$

$=-11$