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Question

limxaa+2x3x3a+x2x

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Solution

ltxaa+2x3x3a+x=2x
Now rationalise.
ltxa a+2x3x× (a+2x+3x)(a+2x+3x) ×13a+x2x ×(3a+x+2x)(3a+x+2x)
ltxaa+2x3x)(3a+x9x)×3a+x+2xa+2x+3x
ltxa /ax3(/ax)×3a+x+2xa+2x+3x
13×4a+2a3a+3a
13/a ((2+2)23/a=233or239).

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