We have,
limx→axsina−asinxx−a
Now,
limx→axsina−asinxx−a00form
Using L’ Hospital rule and we get,
limx→axddxsina+sinaddxx−addxsinxddxx−ddxa
⇒limx→ax×0+sina×1−acosx1−0
⇒limx→asina−acosx
Taking limit and we get,
⇒sina−acosa
Hence, this is the answer.