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Question

limxπ5+cos x2(πx)2

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Solution

limxπ5+cos x2(πx)2

xπ,thenπx0,letπx=y

=limy05+cos(πy)2y2

=limy05cos y2y2

=limy0(5cos y)2y2×(5cos y+2)(5cos y+2)

=limy0(5cos y4)(5cos y+2)

=limy02sin2y2(5cos y+2)

=2×(limy0sin y2y2)2×141limy0((5cos y)+2)

=2×14×14+2=2×14×14

=18


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