${lim}_{x \to 0} \frac{sin (x)}{x + 1}$

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Solution

Given,
${lim}_{x \to 0} (\frac{sin (x)}{x + 1})$
$= \frac{sin (0)}{0 + 1}$
$= \frac{0}{1}$
$= 0$

Hence, this is the answer.

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