By subsituing limit as 1 the expression takes the form 00 Using L Hospiatls Rule #160; lim_x→ 114x+1=15 #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of Sets

limx→ 1x -12x...

Question

$l i m_{x \to 1} \frac{(x - 1)}{(2 x^{2} + x - 3)}$

Open in App

Solution

By subsituing limit as $1$ the expression takes the form $\frac{0}{0}$
Using L Hospiatls Rule
${lim}_{x \to 1} \frac{1}{4 x + 1} = \frac{1}{5}$

Suggest Corrections

Similar questions

{lim}_{x \to 1} \frac{x - 1}{2 x^{2} + x - 3}

\lim_{x \to 1} \{\frac{x - 2}{x^{2} - x} - \frac{1}{x^{3} - 3 x^{2} + 2 x}\}

lim x \to 1 \frac{x - 1}{2 x^{2} - 7 x + 5}

lim x \to 1 \frac{x - 1}{2 x^{2} - 7 x + 5} = - \frac{1}{b} .

b

lim x \to 1 \frac{(2 x - 3) (\sqrt{x} - 1)}{2 x^{2} + x - 3}

Join BYJU'S Learning Program