Question

$li{m}_{x\to 1}$ $\frac{logx}{x-1}$ =
[Rpet 1996; MP PET 1996; P.CET 2002]

• A. 1
• B. -1
• C. 0
• D.

Answer 1

The correct option is A

1

$li{m}_{x\to 1}$ $\frac{log\left[\right(x-1)+1]}{x-1}$ = 1
Aliter : Apply L-Hospital's rule,
$li{m}_{x\to 1}$$\frac{logx}{x-1}$ = $li{m}_{x\to 1}$$\frac{\left(\frac{1}{x}\right)}{1}$ = 1