${lim}_{x \to 4} \frac{x^{2} - 16}{x - 4}$

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Solution

${lim}_{x \to 4} \frac{x^{2} - 16}{x - 4} {lim}_{x \to 4} \frac{(x - 4) (x + 4)}{x - 4} {lim}_{x \to 4} x + 4 = 4 + 4 = 8$

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{lim}_{x \to 4} \frac{x^{2} - 16}{x - 4} = 4

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