wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

limx0 5x-14+x-2

Open in App
Solution

limx0 5x-14+x-2

Rationalising the denominator, we get:

=limx0 5x-1 4+x+24+x-2 4+x+2=limx0 5x-1 4+x+24+x-4=limx0 5x-1x 4+x+2 limx0 ax-1x=log a=log 5×4+0+2=4 log 5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon