wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

limx0 log a+x-log ax

Open in App
Solution

limx0 log a+x-log ax=limx0 log a+xax=limx0 log 1+xaxa×a=1a×1=1a

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon